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I flagged this as a duplicate of that.

I m not asking why it is not considered a duplicate; I agree that it is not a duplicate.

What is strange about it, is that I have never* seen a duplicate flag being declined before. They are either "helpful" or "aged away".

When are duplicate-flags declined?

(Note: This refers to my 2k helpful flags on SO)

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    $\begingroup$ As for why a dupe flag never gets declined on SO and it ages away, that's because SO is a giant community full of bad questions. $\endgroup$
    – M.A.R.
    Commented Oct 11, 2016 at 7:28
  • $\begingroup$ @Rubisco I think your comment should be part of your answer, since the only way someone would think dupe-flags cant get declined is because he has been flagging only on SO. $\endgroup$
    – user
    Commented Oct 11, 2016 at 17:16
  • $\begingroup$ Fermi meh, I'll keep the answer to the point. There is always some interesting discussion to be had about moderation on these communities and on SO. You can visit this chat or our chemistry chat for a little friendly discussion. $\endgroup$
    – M.A.R.
    Commented Oct 11, 2016 at 17:26

1 Answer 1

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Duplicate flags do get declined when a moderator declines them. There are only two ways to dismiss a flag, marking as helpful and declining.

Here's something from meta.SE that makes this answer look authoritative.

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    $\begingroup$ Yes, I killed that flag instantly. It was at a time where I had the feeling a lot of questions were closed as duplicates because the answer of a different question would also fit, while the questions itself were significantly different. $\endgroup$ Commented Oct 11, 2016 at 7:50
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    $\begingroup$ Let us honour the flag gone from us with a moment of silence. $\endgroup$
    – Jan
    Commented Oct 11, 2016 at 19:25
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    $\begingroup$ @Martin-マーチン I think this could be much better emphasized, that 'VTC b/c duplicate' is only for when the question is a duplicate, and not the answer. It made sense when you laid it out (in chat one time, I think? maybe in a comment thread), but I hadn't thought of it that way before. $\endgroup$
    – hBy2Py
    Commented Oct 15, 2016 at 17:45

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