8
$\begingroup$

Sandbox II has become as clogged as Sandbox I was (and is), especially for users with 10,000 reputation or above. So, here is a new new post...

Before you delete a post here, please reduce it to one line without MathJax.


Old formatting sandboxes:

$\endgroup$
3
  • $\begingroup$ Why do we have to reduce it to one line without MathJax? $\endgroup$
    – Micelle
    Jun 19, 2020 at 14:53
  • 8
    $\begingroup$ @Micelle deleted posts are viewable by users with >10,000 reputation, so it's just a courtesy thing. Long mathjax posts make the page load slowly. $\endgroup$ Jun 19, 2020 at 14:55
  • 1
    $\begingroup$ @orthocresol, moving your comment explanation into the question would improve it. $\endgroup$ Feb 9 at 15:00

8 Answers 8

7
$\begingroup$

Common misspellings

This table is indexed alphabetically in the first column. Please feel free to add to it.

The second column contains a link to the appropriate Wikipedia page.

Wrong Correct Remarks
Breddts Bredt’s [rule] Julius Bredt.
carbonation carbocation Carbonation is what you do to make fizzy drinks.
Clemenson Clemmensen [reduction] Erik Christian Clemmensen.
die dye “Die” is only for “die Farbstoffe”.
Diel's Adler Diels–Alder [reaction] Otto Paul Hermann Diels; Kurt Alder.
fajan's Fajans’ [rules] Kazimierz Fajans
flourine fluorine
Friedel–Craft's Friedel–Crafts The guy's name was James Crafts, not James Craft.
gasses gases One outgasses gases.
Gibb's Gibbs [energy] Josiah Willard Gibbs.
Henderson–Hasselbach Henderson–Hasselbalch [equation] Lawrence Joseph Henderson; Karl Albert Hasselbalch.
iconic ionic [bond]
morality molarity The moral of this story is that only people can be moral or amoral.
Nerst Nernst [equation] Walther Hermann Nernst.
phosphorous phosphorus This refers to the element (as a noun, not adjective). See also next entry.
phosphorus acid phosphorous acid This refers to the acid $\ce{H3PO3}$. See also previous entry.
pie pi/π [bond] Pie bonding is for SeasonedAdvice.SE.
seperation separation [process] “Seperate” is not even an English word.
stigma sigma/σ [bond] Stigma bonding is for Christianity.SE or MedicalSciences.SE.
Tollen's Tollens’ [reagent] Bernhard Tollens.
Vander-Wal's, Van der walls van der Waals [force] Johannes Diderik van der Waals. Note it's lowercase “v”.
Vant-hoff van 't Hoff [equation] Jacobus Henricus van 't Hoff.
$\endgroup$
6
$\begingroup$

Somebody complained that the reaction I asked about doesn't exist. Why is this a problem?

Chemistry is an experimental science first and foremost, and this is especially true of synthetic chemistry, whether organic or inorganic.

What this means is that: we don't come up with theories from first principles, then use them to predict reactions. [We're getting better at doing this using quantum mechanics, but it's still very early days.] Instead, we find out that a reaction happens, and then we work backwards to come up with a model that explains it.

The ultimate source of "truth" in chemistry is not defined by our theories, but rather by our experimental observations. The theories only exist because they can explain experimental evidence.

[Incidentally, that's why there are so many exceptions to the theories. Many of them have a limited range of validity, in that they can only explain a certain subset of the experimental observations we have. A simple example is the octet rule. It works for quite a lot of organic molecules, but can completely fall apart in other contexts.]

So, asking "why does this reaction occur?" is only sensible if that reaction has actually occurred!

If nobody has done it before in real life, then we have no way of knowing whether it would actually occur. And secondly, if it doesn't actually occur and we come up with a theory to explain it, then there is no guarantee that that theory would be correct.

$\endgroup$
4
$\begingroup$

Temporary place to get answers and such put together. Everything I post here will be deleted in a couple of days or so. A tidy sandbox is a good sandbox!

$\endgroup$
1
  • $\begingroup$ Cheers Ed, I've screenshotted this! I use Engineering Equation Solver (EES) so should be able to get something going in there :) $\endgroup$
    – Hendrix13
    Aug 13 at 3:12
1
$\begingroup$
Substance $\Delta H^\circ_\mathrm{f}$ / $\pu{kJ mol-1}$ $\Delta G^\circ_\mathrm{f}$ / $\pu{kJ mol-1}$ $S^\circ_\mathrm{f}$ / $\pu{J mol-1 K-1}$
$\ce{CH4(g)}$ $-75$ $-51$ $186$
$\ce{CO(g)}$ $-111$ $-137$ $198$
$\ce{CO2(g)}$ $-394$ $-394$ $214$
$\ce{H2O(l)}$ $-286$ $-237$ $70$
$\ce{H2O(g)}$ $-242$ $-229$ $189$
$\ce{O(g) }$ $249$ $232$ $161$
$\ce{O2(g) }$ $0$ $0$ $205$
$\ce{O3(g) }$ $143$ $163$ $239$
$\ce{H2(g)}$ $0$ $0$ $131$
$\ce{C(s)}$ $0$ $0$ $6$
$\endgroup$
6
  • 2
    $\begingroup$ :P Well, if you'll forgive me: the negative numbers should be written with actual minus signs, hyphens are a bit shorter. IMO the easiest is to just use MathJax for everything, i.e. do $-75$, that will automatically use minus signs and also makes the font a bit more consistent throughout. $\endgroup$ Apr 19 at 12:24
  • $\begingroup$ @orthocresol Next thing, I'll worry about left or right justification of the items... $\endgroup$ Apr 19 at 12:38
  • $\begingroup$ Yeah, it would be nice to have the numbers aligned after the negative sign! $\endgroup$ Apr 19 at 12:40
  • $\begingroup$ @KarstenTheis My take on this is to align numbers by a decimal point and flush them right. Since MD tables are r̶̶e̶̶t̶̶a̶̶r̶̶d̶̶e̶̶d̶̶ limited in terms of formatting options, just align the numbers right with |--:| and, if applicable, round them up to the same decimal point so that one can easily visually compare the values. Also, I think missing values are better denoted with "NA" rather than with an em dash, and a slash serves a better (and mathematically correct) separator for quantity symbols and units in a header. $\endgroup$
    – andselisk Mod
    Apr 19 at 12:58
  • 1
    $\begingroup$ @andselisk I am learning more today than my students this entire semester. I changed it to "0" instead of "NA" for the elements in their most common allotrope. $\endgroup$ Apr 19 at 14:39
  • $\begingroup$ @KarstenTheis One more thing: if you have a choice, it's better to use a font with monospaced numbers. Zero wiggle in character length assists a lot with the visual comparison of long numbers. $\endgroup$
    – andselisk Mod
    Apr 19 at 15:55
0
$\begingroup$

$h=\frac{I_{\text{const}}\cdot R_{\text{ref}}(1+\alpha\Delta T)}{A_{\text{filament}}(T-T_{\text{flow}})}$

$\endgroup$
0
$\begingroup$

The following are the definitions of 'mole' represented in the form of equations:

(1) Number of moles of molecules $=\frac{\text { weight in } g}{\text { molecular weight }}$

(2) Number of moles of atoms $=\frac{\text { weight in } \mathrm{g}}{\text { atomic weight }}$

(3) Number of moles of gases $=\frac{\text { volume at NTP }}{\text { standard molar volume }}$ (Standard molar volume is the volume occupied by 1 mole of any gas at NTP, which is equal to $22.4$ litres.)

(4) Number of moles of atoms / molecules / ions / electrons $=\frac{\text { no. of atoms } / \text { molecules } / \text { ions } / \text { electrons }}{\text { Avogadro constant }}$

(5) Number of moles of solute $=$ molarity $\times$ volume of solution in litres or no. of millimoles = molarity $\times$ volume in $\mathrm{mL}$.

$\frac{\text { Millimoles }}{1000}=$ moles

(6) For a compound $\mathrm{M}_{\mathrm{x}} \mathrm{N}_{\mathrm{y}}, x$ moles of $\mathrm{N}=y$ moles of $\mathrm{M}$

$\endgroup$
-1
$\begingroup$

$\require{begingroup}\begingroup$ $\def\pi{\neq 3.14}$

$\require{begingroup}\begingroup$ $\def\pi{\neq 3.14}$

The ratio of a circle's circumference to its diameter is $\pi$.

The ratio of a circle's circumference to its diameter is $\pi$.

$\endgroup$

$\endgroup$

$\endgroup$
1
  • 1
    $\begingroup$ $\pi here doesn't leak through: $\pi$ $\endgroup$ Jan 30, 2021 at 15:15
-1
$\begingroup$

Such a compound exists $\ce{HCOOOH}$

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .